Reference Circle → Simple Harmonic Motion

Watch the projection of uniform circular motion on a diameter. The projected point executes SHM.

Angle, θ
Displacement, x/A1.00
Period, T2.00 s
Angular frequency, ω3.14 rad/s

Controls

1.00
The radius of the reference circle becomes the SHM amplitude.
0.50 Hz
Uniform rotation and the projected SHM have the same period.
Phase determines where the rotating point starts.
Observe: The horizontal coordinate of the rotating point is exactly the SHM displacement.
θ = ωt + φ    and    x = A cos θ

Reference circle and projection

SHM axis θ equilibrium −A +A x
rotating point SHM projection angle θ

Displacement–time graph

+A 0 −A time
Predict before changing a control

Increase the frequency. What happens to the rotation speed and the SHM period?